(2x^3-3x^2+x)-(x^2-1)+4x^2=0

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Solution for (2x^3-3x^2+x)-(x^2-1)+4x^2=0 equation:


Simplifying
(2x3 + -3x2 + x) + -1(x2 + -1) + 4x2 = 0

Reorder the terms:
(x + -3x2 + 2x3) + -1(x2 + -1) + 4x2 = 0

Remove parenthesis around (x + -3x2 + 2x3)
x + -3x2 + 2x3 + -1(x2 + -1) + 4x2 = 0

Reorder the terms:
x + -3x2 + 2x3 + -1(-1 + x2) + 4x2 = 0
x + -3x2 + 2x3 + (-1 * -1 + x2 * -1) + 4x2 = 0
x + -3x2 + 2x3 + (1 + -1x2) + 4x2 = 0

Reorder the terms:
1 + x + -3x2 + -1x2 + 4x2 + 2x3 = 0

Combine like terms: -3x2 + -1x2 = -4x2
1 + x + -4x2 + 4x2 + 2x3 = 0

Combine like terms: -4x2 + 4x2 = 0
1 + x + 0 + 2x3 = 0
1 + x + 2x3 = 0

Solving
1 + x + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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